I think, you are involved in the math division of numbers, so you need to do undertaking has of finding the quotient and the remainder in the division of two positive numbers. Do most of “quotients, remainders” and you bring to aptitude an image like this:
In this example, we are solver dividing 1220 by 200 and we are find the quotient to be 6 and the remainder to be 20 using dividing 1220 by 200. The division problem has the dividend and the divisor as its given value; in the example, these are, in that order, 1220 and 200. Results have of the quotient and the remainder, which, in the example, are 6 and 20, in that order.
Think about the solver division of number are 27 % 5= 5 remainder 2. It may also be written as
`27/5`=2+(`25/5`)
In solver division using algorithm, 27 is called the dividend, 5 the divisor, 5 the quotient, and 2 the remainder. The relation between these four quantities can also be representation as 27=5x5+2.
In fact, given any integers g and h (h not equal to 0) there exist only one of its kind integers q and r, where 0≤ r<h, such that g=hq+r
This solver division algorithm is referred to as the math division decimals or the division independence.
If you require to do divide g by h (b not equal to 0), we get `g/h`=q=`r/h`, which makes the solver division algorithm almost clear.
When g is divided by h we get a quotient q and a remainder r, 0 ≤r<h, and this cannot be ended in more than one way (q and r are only one of its kind).
Division solver need to follow the step:
Given: solver division positive numbers g and h.
Result: non-negative numbers q and r such that g=hq+r, and 0≤r<h.
Steps you need to do for division solver:
Step 1: Begin by set Q=0 and R=g.
Step 2: if R<h, write down, “The quotient is Q and the remainder is R” and stop; or else, go to do step 3.
Step 3: If R≥h, take off b from R, boost Q by 1, and go back to step 2.
Problems on Division Solver:
Problem 1:- Division problem solver 23 by 68
Solution:-
In following steps for how to do divide 23 by 68
Step 1:-
-------
23| 68
In the above equation 23 is divisor and 68 is dividend. In the divisor has two decimal numbers put the value dividend of 23.
2
-------
23| 68
46
---------
22
In 23 x 2 = 46 the divisor number 23 is multiplied with 2 to get an answer 46. In 46 is less than from 68.So use the value then subtract the value and get 22.
Step 3:-
2.9
-------
23| 68
46
---------
220
207
---------
13
The value 22 has no more value in the right side. So put 0 to get 220 and put decimal point on the quotient. Then normal dividing 23x 9 = 207 the divisor number 23 is multiplied with 9 to get an answer 207. In 207 is less than from 220.So use the value then subtract the value we get 13
Step 4:-
2.95
-------
23| 68
46
---------
220
207
---------
130
115
---------
15 (continued)
The value 13 has no more value in the right side. So put 0 to get 130 and put decimal point on the quotient. Then normal dividing 23x 5 = 115 the divisor number 23 is multiplied with 5 to get an answer 115. In 115 is less than from 130.So use the value then subtract the value we get 2.95
Problem 2:- Division problem solver 96 by 4 Solution:-
In following steps for how to divide 96 by 4
Step 1:-
-------
4| 96
In the above equation 4 is divisor and 96 is dividend. In the divisor has two decimal numbers put the value dividend of 96.
Step 2:-
2
-------
4| 96
8
---------
16
In 4 x 2 = 8 the divisor number 4 is multiplied with 2 to get an answer 16. In 8 is less than from 9.So use the value then subtract the value and get 1.
24
-------
4| 96
8
---------
16
16
----------
0
----------
In 4 x 4 = 16 the divisor number 4 is multiplied with 4 to get an answer 16. In 16 is equal to 16.So use the value then subtract the value and get remainder is 0.
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