Introduction:
Two different quantities having different percentage of needed substances can be mixed together to get the desired amount. This is called mix word problem in math. For example: Let X and Y be two different solutions. Each are having different percentage of Salt in it. Those two X and Y can be mixed together to get the required percentage of the final solutions.
Now let us see few problems of this kind.
Example Problems on Mix Word Problems Math:
Ex 1: Two salt solutions having 12% and 36% of salts respectively in them. They are added together to form 40% of salt solution. If 280 liters of 12% salt solution is added, how many liters of 36% has to be added?
Soln: Let x be the salt solution.
Given: `36/100` x + `12/100` `xx` 280 = `40/100` (X + 80)
`=>` 36x + 3360 = 40x +3200
`=>` 40x – 36x = 3360 – 3200
`=>` 4x = 160 `=>` x = 40 liters.
Ex 2: Two oils have to be mixed together. One of the oil has 15% of the required content and the other has 30% of the required content. How many liters of 30% of oil have to be added to 290 liters of 15% of the oil, so that we can have a mix of 42% of the oil content?
Soln: Let X be the amount of oil with 30% content in it.
Given: `30/100` (x) + `15/100` (290) = `42/100` (x + 90)
`=>` 30x + 15`xx` 290 = 42x + 42`xx` 90
`=>` 12x = 4350 – 3780
`=>` x = `570/12` = 47.50 liters
More Example Problem on Mix Word Problems Math:
Ex 3: Two herbals have to be mixed together. One of them has 25% of the required vitamins and the other has 35% of the required vitamins. How many liters of 25% of herbal have to be added to 120 liters of 45% of herbal, so that we can have a mix of 40% of vitamins?
Soln: Let x be the amount of herbal with 25% vitamin in it.
Given: `25/100` (x) + `45/100` (120) = 40/100 (x+120)
`=>` 25x + 5400 = 40x + 4800
`=>` 15x = 5400 – 4800 = 600 `=>`x = `600/15`
x = 40liters
