Find Domain off

Introduction of Domain function

The domain of definition or simply the domain of a function is the set of "input" or argument values for which the function is defined. That is, the function provides an "output" or "value" for each member of the domain. The domain of cosine is the set of all real numbers, while the domain of the square root consists only of numbers greater than or equal to 0 when the Function is represented in an xy


Examples


Problem 1: Find the domain of the real valued linear function f given below.

f(x) = x + 1

Substitute x=1, 2,3,4,5

x=1                    f(x) =1+1

By solving it we get

f(x) =2

The ordered pair is (1, 2)

x=2                            f(x) =2+1

By solving it we get

f(x) =3

The ordered pair is = (2, 3)

x=3         f(x) =3+1

By solving it we get

f(x) =4

The ordered pair is = (3, 4)

x=4                          f(x) =4+1

By solving it we get

f(x) =5

The ordered pair is = (4, 5)

x=5                            f(x) =5+1

By solving it we get

f(x) =6

The ordered pair is = (5, 6)

The domain function is 1, 2,3,4,5

Problem 2: Find the domain of the real valued linear function f given below.

f(x) = 2x + 1

Substitute x=1, 2,3,4,5

x=1                       f(x) =2(1)+1

By solving it we get

f(x) =3

The ordered pair is (1, 3)

x=2                          f(x) =(2*2)+1

By solving it we get

f(x) =5

The ordered pair is = (2, 5)

x=3                           f(x) = (3*2)+1

By solving it we get

f(x) =7

The ordered pair is = (3, 7)

x=4                      f(x) =(4*2)+1

By solving it we get

f(x) =9

The ordered pair is = (4, 9)

x=5,                           f(x) =(5*2)+1

By solving it we get

f(x) =11

The ordered pair is = (5, 11)

The domain function is 1, 2,3,4,5


Practice problem


Problem : Find the domain of the real valued linear function f given below.

f(x) = 2x + 5